Question

What is the volume occupied by 30g of neon gas at 400k and 0.821 bar?​

Answer 1

Answer:

V = 42.43 L

Step-by-step explanation:

According to the ideal gas law,

PV=nRT

• P = pressure
• V = volume
• n = no. of moles = 20/3  = 1.5
• T = temperature
• R = gas constant = 0.0821 L atm mol−1  K  −1

 

Therefore V =  nRT/P

V = 1.5×0.0821×340 /(750/760)  

V = 42.43 L

Answer 2

Answer:

hope it will help you

Step-by-step explanation:

please mark it as Brian list a s