Question

What is the volume occupied by 4.4 g of CO2 at NTP? a. 22.4 L b. 2.24 L c. 0.224 L d. 0.1 L Provide me the answer with full solution as soon as possible.

Answer 1

Answer:

Given mass=4.4

Molar mass of co2= 44

thus, Volume/22.4 = Given mass/molar mass

Volume = 4.4 x 22.4/44

Volume = 2.24L

Explanation:

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Answer 2

Explanation:

The  formula related ton number of mole = given weight /molecular weight .It is given that  weight of Carbon dioxide,CO2 = 4.4 g. Since,  molecular weight of CO2 = atomic mass of Carbon  + 2 × atomic mass of Oxyge. we know, atomic weight  of oxygen, {e.g., O} is 16g/mol and atomic weight of  carbon,  C is 12g/mol .Therefore, molecular weight  of CO2 = 12 + 2 × 16 = 12 + 32 = 44g/mol .Number of moleis  = 4.4/44 = 0.1 .From Avogadro’s hypothesis , 1 mole of an ideal gas at STP occupies  22. 4L volume .Therefore, 0.1 mole of CO2 occupied 22.4 × 0.1 = 2.24L volume at STP .Therefore, answer is  option (b)2.24L.