Question

What is the volume occupied by 4.4 g of CO2 at STP? a. 22.4 L b. 2.24 L c. 0.224 L d. 0.1 L Provide me the answer with full solution as soon as possible.

Answer 1

first, use formula , number of mole = given weight /molecular weight

given, weight of Carbon dioxide = 4.4 g

as we know , molecular weight of CO2 = atomic mass of C + 2 × atomic mass of O

we know, atomic mass of oxygen, {e.g., O} is 16g/mol
and atomic mass of carbon {e.g., C} is 12g/mol

so, molecular mass of CO2 = 12 + 2 × 16 = 12 + 32 = 44g/mol

now, number of mole = 4.4/44 = 0.1

A basic concept is that, 1 mole of an ideal gas at STP occupied 22. 4L volume .

so, 0.1 mole of CO2 occupied 22.4 × 0.1 = 2.24L volume at STP { standard temperature and pressure} .

answer answer should be option (b)2.24L

Answer 2

Answer:

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Explanation:

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