Question

What is the volume of 0.1M Ca (OH) 2 needed for the neutralisation of 40ml of 0.05M oxalic acid?

Answer 1

Answer:

v =20 ml

Explanation:

V1N1=V2N2

40X0.05=0.1XV2

2=0.1XV2

2/0.1=V2

20 mL of 0.1 M Ca(OH)2

0.0020 = 0.1 * v

v = 0.02 l

v =20 ml

Answer 2

Answer:

v =20 ml

Explanation:

Answer:

v =20 ml

Explanation:

V1N1=V2N2

40X0.05=0.1XV2

2=0.1XV2

2/0.1=V2

20 mL of 0.1 M Ca(OH)2

0.0020 = 0.1 * v

v = 0.02 l

v =20 ml