what is the volume of 2 mole of water
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No. of moles(n) = Given volume(v) / Volume of an ideal gas at STP (V)
Given , n=2 , We know , V = 22.4L
So , v = nV = 2*22.4L = 44.8L
Given , n=2 , We know , V = 22.4L
So , v = nV = 2*22.4L = 44.8L
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