what is the volume of 200.0 g of carbon monoxide at STP
Answers
Answered by
1
Answer:
V=160.0L
Explanation:
I hope this will help u
Answered by
0
Answer:
160 L
Explanation:
At stp 28g of co occupy 22.4 L
=> 200g of co occupy = [ 200 * 22.4 ] /28 = 160 L
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