what is the volume of 6 gram of
hydrogen at 1 atm and zero degree C
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Hi again,
PV= nRTHere, P= 1 atmN= given weight/ molecular weight= 6/2 = 3( We take molecular weight as hydrogen exists a molecule in nature)R= o.o821 atm liter mol^-1 kelvin^-1T= o degrees = 273 kTherefore,V= 3 x 0.0821 x 273 = 67.2399
Hope it helps!
PV= nRTHere, P= 1 atmN= given weight/ molecular weight= 6/2 = 3( We take molecular weight as hydrogen exists a molecule in nature)R= o.o821 atm liter mol^-1 kelvin^-1T= o degrees = 273 kTherefore,V= 3 x 0.0821 x 273 = 67.2399
Hope it helps!
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