Question

What is the volume of a cylindrical tank whose base area is 27sq.m. and depth is 12m?​

Answer 1

Step-by-step explanation:

volume = area of base *height

= 27*12 = 324 cm^3

Answer 2

Given

In a cylindrical tank,

Area of the base =27 sq.m

Depth(height)=12m

To find

Volume of the cylinder

Explanation:

$\sf \: area \: of \: the \: base = 27 {m}^{2}$

$\sf \: \pi {r}^{2} = 27m^{2}$

Now

$\underline{ \sf \: volume \: of \: the \: cylinder \: = \pi {r}^{2} h \: cubic \: units}$

substituting the values

$V=\pi\:r^2h$

$=>V=27×12$

$=>V=324 m^3$

$\boxed{\underline{\sf volume \: of \: the \: cylinder=324m^3}}$

Some important formulas:

For a cylinder,

$=>C.S.A =2\pi\:rh$

$=>T.S.A=2\pi\:r(r+h)$

here

h=height or depth of the cylinder

r=radius of the base