What is the volume of carbon dioxide gas produced by heating 1 kg of calcium carbonate in STP?
Answers
Answered by
1
Answer:
As we can see here that 1 mol of calcium carbonate gives 1 mol of carbon dioxide. So, according to the balanced reaction, 100g of CaCO3 produces 100g of carbon dioxide. Hence, at STP, 11.2L of carbon dioxide is obtained by thermal decomposition of 50g of calcium carbonate.
Answered by
1
Answer:
22.4 L
Explanation:
At STP, the molar volume of any ideal gas is 22.4 L. We can identify condition “1” as the volume, temperature, and pressure of the CO2 sample at laboratory conditions and condition “2” as STP.
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