What is the Volume of co2 obtained at STP by the complete decomposition of 9.85 g BaCo3
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BaCO3=BaO + CO2
1 mole baco3 gives 1 mole carbon dioxide
9.85gram =0.05 moles baco3
hence 0.05 moles of co2 produced
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1 mole baco3 gives 1 mole carbon dioxide
9.85gram =0.05 moles baco3
hence 0.05 moles of co2 produced
pls mark as brainliest
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