Two buses start from a bus terminal with a speed of 20 km/h at interval of 10 minutes. what is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes
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Answered by
5
Let the speed of the man be
x
x km/hr
Speed is inversely proportional to the time (when distance is constant).
Here the distance between the buses remains constant.
20 kmph is inversely proportional to 10 minutes
(20+x) kmph is inversely proportional to 8 minutes
⇒
20×10=
(
20
+
x
)
×
8
200
=
160
+
8
x
40
=
8
x
x
=
5
x
x km/hr
Speed is inversely proportional to the time (when distance is constant).
Here the distance between the buses remains constant.
20 kmph is inversely proportional to 10 minutes
(20+x) kmph is inversely proportional to 8 minutes
⇒
20×10=
(
20
+
x
)
×
8
200
=
160
+
8
x
40
=
8
x
x
=
5
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