What is the volume of oxygen liberated at STP when 24.5 g of potassium chlorate is subjected to
heating?
(a) 3.36 L
(b) 5.6 L
(c) 6.72 L
(d) 16.8 L
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Answer:
336 L of oxygen at STP are liberated by heating 12.25 gram of. Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number of particles
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