Question

what is the volume of water to be added to 200 ml of 18 M H2SO4 solution to get 1.8 M H2SO4 solution ​

Answer 1

Answer:

We know that

molecular mass of Sulphuric Acid =  (2∗1)   +   (1∗32)   +   (4∗16)  =  98u.  

Now ,

The number of moles of  H2SO4  in 2.45 grams is

n =  2.4598  =  0.025mol.  

Now the concentration is

[H2SO4]   =   18   Molar  =  18   moleslitre  

Since

18 moles are present in 1 litre ,

1 mole is present in  118  litres , and

0.025 moles are present in 0.025  ∗118 litres

0.025 moles are present in 0.001389 litres = 1.389 mL .

Thus , 1.389 mL of 18 M Sulphuric Acid contain 2.45 grams Sulphuric Acid

Explanation: