What is the wave number of 4th line in balmer series of hydrogen spectrum?
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Answer:
Explanation:
wave number = R*Z²*[1/(n1)²-1/(n2)²]
here n1 =2 , n2 =6
wave number =1.1*10^(7)[1/(2)²-1/(6)²] = 2.44*10^(6)
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