Question

What is the wavelength of light emitted when the electron in a hydrogen at
undergoes transition from an energy level with n = 4 to an energy level with n =​

Answer 1

Answer:

The expression for the wavelength of radiation is, 

λ1=R(n121−n221) 

Substitute values in the above expression,

λ1=109677×(221−421)=109677×(41−161)=109677×(6412) 

λ=4.86×10−5cm=486×10−9m=486nm.

Explanation:

hope this helps you mate

please mark as brainliest