Question

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n = 5 to an energy level with n = 3? use Rh =109678 per cm​

Answer 1

Answer:

Here is your answer mate.....

Explanation:

According to Balmer formula

Wave number =Rh[1/n^21-1/n^2 2].

Here n1=2,n2=4,Rh=109678

Putting these values in the equation we get

Wave number =109678(1/2^2-1/4^2)=109678 X3/16

Also λ=1/ wave number

Therefore λ=16/109678×3

=486nm

please mark it as brainliest...

NOTE-ALL THE NUMBERS ARE IN DOWN CASE, i.e. BELOW THE NUMBER

IF IT IS IN A RAYS TO FORM IT IS MENTIONED ABOVE..

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