Question

what is the wavelength of photon that has an energy of 4.38 × 10 to the power minus 18 Joule in angstrom?

Answer 1

Answer:

kinetic energy of the alpha particles=$6.8*10^{-18} J$

we already know that

E=hv

h=$6.626*10^{-34} m^{2} kg/s$

v=$(6.8*10^{-18} J)/(6.626*10^{-34} m^{2} kg/s)$

 =$1.026*10^{21} Kz$

λv=c

c=$3*10^{8} m/s$

v=$1.026*10^{21} Hz$

wave length(λ)=$(3*10^{8} m/s)/(1.026*10^{21} Hz)$

                       =$2.924*10^{-13} m$