Question

What is the weight of BaCl which reacts with 2.36g of NaSO4 which gives 3.88g of BaSO4 and 1.94g NaCl.

Answer 1

let mass of sodium sulphate = x
x + mass of barium chloride = mass of sodium chloride + mass of barium sulphate
x + 5.22 =6.10 +2.80
x= 8.9 - 5.22
x = 3.68 g

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Answer 2

$\mathfrak{\purple{\huge{Hello\:Mate!!!}}}$

$<b><u>Answer</u></b>$

$<b>The weight of BaCl is 3.46g</b>$

$<b><u>Step-by-step explanation</u></b>$

Barium chloride + Sodium Sulphate ---> Barium Sulphate + Sodium chloride

BaCl + NaSO4 ----> BaSO4 + NaCl

Let x be the weight of BaCl.

x + 2.36g ---> 3.88g + 1.94g

x + 2.36g -----> 5.84g

x = 5.84g - 2.36g

$<b>x = 3.46g</b>$

$<b>As we know, the rectant will be equal to the product in a chemical reaction.</b>$


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