Question

what is the weight of hydrogen at stp could be contain in a vessal that holds 4.8gms of oxygen at stp

Answer 1

We need a stoichiometric equation for water synthesis:

H2(g)+12O2(g)→H2O(l)

Clearly, dihydrogen must be present in a 2:1 molar ratio with respect to dioxygen.

Moles of dihydrogen

=

4.8⋅g2.01⋅g⋅mol−1

=

2.39⋅mol

Moles of dioxygen

=

38.4⋅g32.0⋅g⋅mol−1

=

1.2⋅mol

Given these molar quantities (they are approx. 2:1) the gases are present in stoichiometric proportion.

2

mol

water are going to be produced.

2⋅mol×18.00⋅g⋅mol−1

=

36⋅g

Answer 2

moles of Oxygen =4.8/32= 0.15
weight of hydrogen = 0.15×2 = 0.3gm