Question

What is the weight of NaOH to be added to 500ml of an acid to increase pH from 2 to 5

Answer 1

Answer:

Mole = concentration x volume

mole of NaOH = 50ml x 0.2 = 10.0

mole of HCl = 50ml x 0.4= 20.0

10 mole of NaOH exactly neutralized by 10 mole of HCl.

NaOH + HCl = NaCl + H2O

that is 20 -10 = 10 HCl mole

Con of H+ = no of mole of H+ / total volume of solution (50+50 ml = 100 ml)

= 10/100 = 0.1

pH = log ( H+)

= log (0.1) = 1

s0 the pH of solution will be one(1) .