what is the weight of o2 required for the complete combustion of 2.85 g of ethylene
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C2H4(ethylene) + 3O2 ———› 2CO2 + 2H2O
Gram atomic mass of ethylene(C2H4) =(2×12+4×1)gm =(24+4)gm =28gm
Gram atomic mass of oxygen (O2) = (2×16)gm = 32gm
For oxydising 1mol of ethylene we require 3mol of Oxygen
∴ For oxidising 2.85 gm of ethylene we require (3×32)gm of oxygen
I.e 96g of Oxygen is required
Gram atomic mass of ethylene(C2H4) =(2×12+4×1)gm =(24+4)gm =28gm
Gram atomic mass of oxygen (O2) = (2×16)gm = 32gm
For oxydising 1mol of ethylene we require 3mol of Oxygen
∴ For oxidising 2.85 gm of ethylene we require (3×32)gm of oxygen
I.e 96g of Oxygen is required
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