Question

What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?
(A) 2.8 kg
(B) 6.4 kg
(C) 9.6 kg
(D) 96 kg

Answer 1

Explanation:

Combustion of Ethylene can be written as:

C2H4 + 3 O2 → 2 CO2 + 2 H2O

0.028 kg (Molar mass of ethylene) needs 3 x 0.032 = 0.096 kg of oxygen.

1 kg of ethylene will need (0.096/0.028) = 3.42 kg of oxygen.

So, 2.8 kg of ethylene will need (3.42 x 2.8) = 9.6 kg of oxygen.