Question

What is the weight of residue obtained after heating of 2.76 of silver carbonate?​

Answer 1

Answer:

2.16 grams of silver

Explanation:

On heating Silver carbonate Ag2CO3 ,

We get

Ag2CO3----> 2Ag + CO2 + 1/2 O2

Molecular weight of Ag2CO3

= 108 X 2 + 12 + 16 X 3

= 276 g.

276 g of Ag2CO3 gives residue

= 2 X 108

= 216 g

Hence, 2.76 g of Ag2CO3 gives the residue as

= 216/276 x 2.76

= 2.16 g of Ag