Question

What is the What is themolality of aqueous solution containing 2.0 g of MgO in 100g of water? 0.1m 0.5m 1.35m​

Answer 1

Answer:

0.5m

Step by step explanation:

Molality = moles of solute / weight of solvent in kg

moles of MgO = given mass / molecular mass

moles = 2/40 = 1/20

molality = 1 × 10/20

molality = 1/2m

=0.5m

Answer 2

Answer:

Explanation:

Disclaimer: What is the molality of an aqueous solution containing $2.0 g$ of $MgO$ in $100 g$ of water?

Solution :

One of the crucial characteristics of solutions is molality. It is mostly based on the mass of the solvent and is used to express the concentration of a solute in a solution. The terms "molality" and "molal concentration" are interchangeable. The letter "m" is typically used to represent it.

The below values are given in the question

The volume of water is $100g$ of water.

The volume of $MgO$ in the water is $2.0g$ .

The moleculess weight of $MgO$ is $(24+16)= 40g$

The formula to get the number of moles is $\frac{volume of MgO}{moleculer weight of water}$ .

Put the values in this expression.

Therefore, the molarity of aqueous solution is $\frac{20}{40}=0.5 gm$

$0.5 gm$ is the correct answer.

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