Question

what is the width and length or rectangle whose area is 36 and perimeter is 26

Answer 1

width=4
length=9......
hope it helps

Answer 2

perimeter = 2 ( L + B ) = 26
thus L + B = 13
Area = L × B = 36
Now
( L + B )^2 = ( 13 )^2
L^2 + 2 LB + B^2 = 169
As LB = 36
L = 36/B
36/B + B = 13
B^2 - 13B + 36 = 0
Solving this quadratic equation gives us two solutions B = 4 And 9
if B = 4
L = 9
and if B = 9
L = 4