Question

What is.The.Work done by 0.2 mole.Of gas at room temperature?

Answer 1

Answer:

here's answer.

Explanation:

• what is the work done by 0.2 mole of gas at room temperature to double it's isobaric process.

= PV = nRT : V2=2v.

. : V1 = V.

T = 273+27= 300°

$p \: \: \: = \frac{nrt}{v}$

w =p∆v

w = p{V2 - V1}

$w \: = \frac{nrtv}{v }$

w = nrt.

W = 0.2 × 8.3 × 300

$w \: \: = 498j$

I hope it's helpful.

please mark me as a brainliest..