Question

What is the work done to increase the velocity of a car from 30km/h to 60 km/h if the mass of the car is 1500 kg?

Answer 1

Work = Change in kinetic energy = 0.5 m (v² - u²) = 0.5 × 1500 kg × [(60 × 5/18 m/s)² - (30 × 5/18 m/s)²] = 156250 joules = 156.25 kJ Work done is 156.25 kJ

Answer 2

Answer:

Work done is 156250 J.

Explanation:

Given,

The mass (m) of the car is 1500 kg.

Initial velocity of car = u = 30 km / hr = 30 * 5/18 = 25 / 3 m/s

Final velocity of car = v = 60 km / hr = 60 * 5/18 = 50/3 m/s

To find: The work to be done to increase the velocity of a car from

30 km h-1 to 60 km h^-1

Solution:

Initial kinetic energy = Ki = 1/2mu² = 1/2*1500*25/3 * 25/3 = 156250/3 J

Final Kinetic energy = Kf = 1/2mv² = 1/2*1500*50/3*50/3 = 625000/3 J

Work done can be given as change in Kinetic Energy,

i.e W = ΔK.E

or, W = Kf -  Ki

or, W = 625000/3 - 156250/3

or, W = 156250 J

Therefore, Work done is 156250 J.