What is the work done to increase the velocity of a car from 30km/h to 60km/h if the mass of the car is 1500kg?
Answers
Answered by
2
From work energy theorem work done is equal to change in kinetic energy
= 1/2m(v^2 - u^2)
= 1/2 × 1500( 16.6 - 8.3)
= 6225 joule
= 1/2m(v^2 - u^2)
= 1/2 × 1500( 16.6 - 8.3)
= 6225 joule
Answered by
0
Answer:
6225J
Explanation:
according to theorem change in kinetic energy is equal to workdone
K.E=W
1/2m(v^2-u^2)
1/2X 1500 (60*5/18+30*5/18)
750 (16.6-8.3)
6225J
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