What is the work done to move charges in a circuit having 6 V potential difference, in which 10 A current flows for ½ minute?
Answers
Answered by
0
Answer:given: current=10A
time=1/2minute=30 sec
V=6V
current=charge/time
therefore,charge=current*time=10*30=300C of charge
V=work done/charge
therefore,work done=V*charge=6*300=1800J/joule
Explanation:
Similar questions