Question

What is the work required for a 74 kg sprinter to accelerate from rest to 2.2m/s

Answer 1

hope u understand the calculations yourself

Answer 2

Answer:

179.08 joules

Explanation:

mass=74kg (given)

initial velocity=0

as we know,v²-u²=2ad

we can write it as v²-u²/2a =d

formula of work is

(mass*acceleration)d

we know that d=v²-u²/2a

now,ma*v²-u2/2a

a (2a) and a in (ma) will be cancelled

we will be left with v²-u²*m/2

(2.2²-0²)*74/2

4.84-0*74/2

4.84*37

179.08 joules(j)