what is the work to be done to increase the speed of 54 km/h to 90 km/h if the mass of the car is 1200 kg
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Hii!!
Mass=1200 kg. (given)
Initial velocity =54 km/h
So, convert it into m/s
Then, 54*5/18 = 15 m/s.
Kinetic energy = 1/2mv^2
1/2*1200*15*15=2,70,000 Joule
Final velocity =90 km/h
So, convert it into m/s.
Then, 90*5/18 = 25 m/s.
Kinetic energy = 1/2mv^2
1/2*1200*25*25= 7,50,000 Joule
Work done= final joule - Initial Joule
7,50,000 - 2,70,000
= 4,80,000 joule
I hope U have get ur answer.
Please mark my answer as brainlist.
Ok thanks
Mass=1200 kg. (given)
Initial velocity =54 km/h
So, convert it into m/s
Then, 54*5/18 = 15 m/s.
Kinetic energy = 1/2mv^2
1/2*1200*15*15=2,70,000 Joule
Final velocity =90 km/h
So, convert it into m/s.
Then, 90*5/18 = 25 m/s.
Kinetic energy = 1/2mv^2
1/2*1200*25*25= 7,50,000 Joule
Work done= final joule - Initial Joule
7,50,000 - 2,70,000
= 4,80,000 joule
I hope U have get ur answer.
Please mark my answer as brainlist.
Ok thanks
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