what is the work to be done to increase the velocity of a car from 30km/hr to 60/hr .if the mass of the car is 1500 kg. help me tomorrow is exam
Answers
Answered by
2
first we have to change the given speed in m/s
so: 30 km/hr = 30 X 1000/3600 =25/3 m/s
60km/hr= 60 X 1000/3600 = 50/3 m/s
mass=1500 kg
then use the formula of kinetic energy=1/2 m(v-u)(v-u)
so by putting the values= 1/2 X 1500(50/3 -25/3)(50/3-25/3)
by solving the equation you can get your answer
so: 30 km/hr = 30 X 1000/3600 =25/3 m/s
60km/hr= 60 X 1000/3600 = 50/3 m/s
mass=1500 kg
then use the formula of kinetic energy=1/2 m(v-u)(v-u)
so by putting the values= 1/2 X 1500(50/3 -25/3)(50/3-25/3)
by solving the equation you can get your answer
Answered by
0
Answer:
Work done is 156250 J.
Explanation:
Given,
The mass (m) of the car is 1500 kg.
Initial velocity of car = u = 30 km / hr = 30 * 5/18 = 25 / 3 m/s
Final velocity of car = v = 60 km / hr = 60 * 5/18 = 50/3 m/s
To find: The work to be done to increase the velocity of a car from
30 km h-1 to 60 km h^-1
Solution:
Initial kinetic energy = Ki = 1/2mu² = 1/2*1500*25/3 * 25/3 = 156250/3 J
Final Kinetic energy = Kf = 1/2mv² = 1/2*1500*50/3*50/3 = 625000/3 J
Work done can be given as change in Kinetic Energy,
i.e W = ΔK.E
or, W = Kf - Ki
or, W = 625000/3 - 156250/3
or, W = 156250 J
Therefore, Work done is 156250 J.
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