Question

What is the zeroes of the polynomial p(x)=x^2+x-6 = 0

Answer 1

this the answer
zero of the give polynomial is -3,2

Answer 2

@

p(x) = x² + x - 6
p(x) = x² + ( 3-2 ) x - 6
p(x) = x² + 3x - 2x -6
p(x) = x(x+3) - 2(x+3)
p(x) = (x+3) (x-2)
Zeros of polynomial
=> (x+3) = 0
(1) => x = -3
=> (x-2) = 0
(2) => x = 2

@:-)