what is value of 1 minus cos theta in terms of sine
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cos2θ= 1 - 2sin^2θ (hope you know this)
∴
2sin^2θ= 1 - cos2θ
∵ we want 1 - cos θ, divide θ by 2
∴the equation gets modified as
2sin^2(θ/2) = 1-cos θ
Thank you
hope it helps
∴
2sin^2θ= 1 - cos2θ
∵ we want 1 - cos θ, divide θ by 2
∴the equation gets modified as
2sin^2(θ/2) = 1-cos θ
Thank you
hope it helps
Ananyasaxena:
it helped much friend
thankyou so much feiend
ur welcome:)
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