what is value of (1525)^0.2 ?
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X=(1525)0.2X=(1525)0.2
X5=1525X5=1525
X5−1525=0X5−1525=0
Now using Newton raphson method
Taking initial value of X as 4.4(guess)and applying the recurrence formulae, where XfXf is final result.
Xf=4.4Xf=4.4−(4.45−1525)/5∗4.44−(4.45−1525)/5∗4.44
Xf=4.4−.064Xf=4.4−.064
Xf=4.336Xf=4.336
Yes, this method requires to calculate the order of 4.4 but its doable in examination within 2 minutes.
hope it help
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X5=1525X5=1525
X5−1525=0X5−1525=0
Now using Newton raphson method
Taking initial value of X as 4.4(guess)and applying the recurrence formulae, where XfXf is final result.
Xf=4.4Xf=4.4−(4.45−1525)/5∗4.44−(4.45−1525)/5∗4.44
Xf=4.4−.064Xf=4.4−.064
Xf=4.336Xf=4.336
Yes, this method requires to calculate the order of 4.4 but its doable in examination within 2 minutes.
hope it help
mark as brainliest
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