Question

What is value of for the A.P. -10, -12, -14, -16,...........
Plz answer it and the answer is -40
He/she will be mark as brainleast

Answer 1

AP is -10,-12,-14,-16...
an= -40
a= -10
d= -12 -(-10)= -2

an=a+(n-1)d
-40= -10+(n-1) -2
-30= -2n+2
-32= -2n
n=16,
IS IT CORRECT,..!!!!

Answer 2

Answer:

16th term is -40.

Step-by-step explanation:

Given : A.P. -10, -12, -14, -16,...........

To find : What is value of for the A.P is -40 ?

Solution :

Given A.P. is  -10, -12, -14, -16,...........

Where, first term is a=-10

common difference is given by $d=-12-(-10)=-12+10=-2$

The nth term is -40.

The nth term is given by,

$a_n=a+(n-1)d$

$-40=-10+(n-1)(-2)$

$-40=-10-2n+2$

$-40=-8-2n$

$-2n=-32$

$n=\frac{32}{2}$

$n=16$

Therefore, 16th term is -40.