what is value of van't hoff factor for KCl and AlCl3 if they are 100% dissociated ?
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Alfa=i-1/n-1
In KCl----- K^+1 + Cl^-1 then n=2
So Alfa=1(due to 100%dissociation)
1=i-1/2-1 then. i=2
InAlCl3-----3Al^+3 +Cl^-1 so n=4
1=i-1/4-1 i=4
In KCl----- K^+1 + Cl^-1 then n=2
So Alfa=1(due to 100%dissociation)
1=i-1/2-1 then. i=2
InAlCl3-----3Al^+3 +Cl^-1 so n=4
1=i-1/4-1 i=4
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0
Answer:
Explanation:
alcl3 will dissociate to al3+ and cl-
so, it will be i= 1+a= 1+3= 4
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