What is what the value of g is more the pole than at the equator?
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As you know that,
g=GM/R*R
here,
'g' stands for acceleration due to gravity
'G' stands for gravitational constant
'M' stands for mass of the earth
'R' stands for radius of the earth
from the above equation,
Radius of the earth 'R' is inversely proportional to 'g'
As you we know earth is not completely circular but elliptical in shape
It is flattened at poles so 'R' is less at poles than at equator
Therefore, less value'R'=more value of'g'
Hence, the value of'g'is more at the poles than equator.
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Ajay Sharma, Forget what we are told before we get too old
Answered Aug 6, 2015
Gravity is inversely proportional to R2R2 (the distance between 2 bodies).
It is represented by Newtonian equation : Gravity=GMmR2Gravity=GMmR2 where G is a gravitational constant, M & m are the masses of the two bodies involved, R is the distance between them.
So, a person standing on poles should feel the same pull by Earth as that on the equator had Earth been a perfect sphere, but it is not it is oval like a rugby ball, so the one on the equator is further away from the center of the ball than the one on those curvy sides of the rugby ball ( think of them as poles ).
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Praveen Hegde
Answered Nov 9, 2016
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We all know that average value of g on earth’s surface is 9.81m/s^2…..
But the value of g varies on the earth surfece as g’ = g—w^2 R cos^2 @ ………. ( sorry.. no superscript available.. )
Where— @ is latitude. w is angular velocity of earth. R is the radius of earth.
So… At the equator @=0° ,
Therefore, g’= g—w^2 R
And at the pole , @=90° ,
Therefore , g’=g
….
Therefore the value of g decreases at equator by w^2 R
…
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Muhammad Nisar Adil, Physics lecturer at Leed Collage Peshawar (2017-present)
Answered Jan 19, 2017
Most people and books say that the value of g at poles is greater than at equator due to the earth is flattened at the poles, but I am not agree with this concept because the poles are at more distance than equator. I think it is only due to the centrifugal force which is greater at the equator and smaller at the pole due to the spinning of earth.
g=GM/R*R
here,
'g' stands for acceleration due to gravity
'G' stands for gravitational constant
'M' stands for mass of the earth
'R' stands for radius of the earth
from the above equation,
Radius of the earth 'R' is inversely proportional to 'g'
As you we know earth is not completely circular but elliptical in shape
It is flattened at poles so 'R' is less at poles than at equator
Therefore, less value'R'=more value of'g'
Hence, the value of'g'is more at the poles than equator.
9.8k Views · View Upvoters
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Upvote· 2425
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Ajay Sharma, Forget what we are told before we get too old
Answered Aug 6, 2015
Gravity is inversely proportional to R2R2 (the distance between 2 bodies).
It is represented by Newtonian equation : Gravity=GMmR2Gravity=GMmR2 where G is a gravitational constant, M & m are the masses of the two bodies involved, R is the distance between them.
So, a person standing on poles should feel the same pull by Earth as that on the equator had Earth been a perfect sphere, but it is not it is oval like a rugby ball, so the one on the equator is further away from the center of the ball than the one on those curvy sides of the rugby ball ( think of them as poles ).
3.7k Views · View Upvoters · Answer requested by Rohit Arora
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Is this answer still relevant and up to date?
Upvote· 56
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Praveen Hegde
Answered Nov 9, 2016
Continue Reading
We all know that average value of g on earth’s surface is 9.81m/s^2…..
But the value of g varies on the earth surfece as g’ = g—w^2 R cos^2 @ ………. ( sorry.. no superscript available.. )
Where— @ is latitude. w is angular velocity of earth. R is the radius of earth.
So… At the equator @=0° ,
Therefore, g’= g—w^2 R
And at the pole , @=90° ,
Therefore , g’=g
….
Therefore the value of g decreases at equator by w^2 R
…
2.7k Views · View Upvoters
Upvote· 23
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Muhammad Nisar Adil, Physics lecturer at Leed Collage Peshawar (2017-present)
Answered Jan 19, 2017
Most people and books say that the value of g at poles is greater than at equator due to the earth is flattened at the poles, but I am not agree with this concept because the poles are at more distance than equator. I think it is only due to the centrifugal force which is greater at the equator and smaller at the pole due to the spinning of earth.
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