Question

What least number being divided by 18, 20, 24 and 30 will leave the remainders
15, 17, 21 and 27 respectively?​

Answer 1

The sum of the digits is 8. Given data: The sum of the digits of smaller number which remainder is 2 upon being divided by 10 25 25.

Answer 2

Question:-

What least number being divided by 18, 20, 24 and 30 will leave the remainders

15, 17, 21 and 27 respectively?

Answer:-

Let the no of division = X

LCM of 18, 20 , 24, 30 =

To find :-

LCM :-

$18 = | 2| \times(3) \times 3 \\ 20 = |2| \times |2| \times (5) \\ 24 = |2| \times |2| \times 2 \times (3) \\ 30 = |2| \times( 3 )\times (5)$

now

find the same number and other number for answer of LCM

there is bracket | | , ( ) like this these number are same and this number multiply only one time

given

$lcm \: = \\ 2 \times 2 \times 2 \times 3 \times 3 \times 5 \\ = > 360$

therefore,

The number required = 360 - X

then ,

find the difference of LCM

$18 - 15 = 3 \\ 20 - 17 = 3 \\ 24 - 21 = 3 \\ 30 - 27 = 3$

difference is 3

Answer :-

$360 - 3 \\ 357$

required = 357

Thanks