Question

what least number must be added to 1056 to get a number extent divisible by 23?

Answer 1

The least no. That must be added to 1056 is 2
Bcoz 23×46=1058
And 1058-1056=2
So the correct answer is 2


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Answer 2

Dividend= Divisors × Quotient + Remainder
1056=23×45+21

Dividend - Remainder
23-21=2

Therefore 2 is the smallest no.added to 1056 to make it completely divisible by 23

CHECK 1056 +2 =1058
1058= 23×46+0