Question

what least number must be added to 1056 to get a number exactly divisible by 23

Answer 1

$firstly \: divide \: the \: number \\ \frac{1056}{23} \\ = \frac{45}{19} \\ as \: we \: seeing \: that \: the \: remainder \\ is \: not \: zero \\ we \: take \: the \: multiple \: of \: \\ 23 \times 2 = 46 \\ so \\ 23 \times 46 = 1056 \\ 1058 = 1056 \\ subtract \\ 1058 - 1056 = 2 \\ \\ number \: added \: = 2$