Question

what least number must be subtracted from 2252 so that the remainder when divided by 7, 15, 21 will leave in each case the same remainder 7?

Answer 1

Answer:

Step-by-step explanation:

Just taking the LCM of 7,15,21

The LCM is 105, it means 105 is divisible by all the numbers that are 7,15,21

Now finding the number which is smaller than 2252 and exact divisible by 105,

The number is 2205 it 21 times of multiple of 105;

21*105=2205;

So 2252-2205=47 is the number subtract from the 2252.

Answer 2

Answer:

40

Step-by-step explanation:

Find the LCM of 7, 15 and 21

7 = 7

15 = 3 x 5

21 = 3 x 7

LCM = 3 x 5 x 7 = 105

Find the remainder when 2252 is divided by 105:

2252 ÷ 105 = 2205 Remainder 47

Find the remainder to subtract:

Remainder = 47

Remainder we want = 7 (Given)

Difference = 47 - 7 = 40

Answer: The number to subtract is 40