What least number should be multiplied to 1719 to get a perfect cube
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Hello Dear!!!!
Here's your answer....
The given number is 1719
we have to do prime factorization....
1719 - 3*3*191
1719 - 3^2 * 191
The power of 3 is 2
the power of 191 is one
To become a perfect cube...the power should be 3
so....we have to multiply 191 two times...and 3 should be multiplied one time...
191*191*3
109443
109443 should be multiplied with 1719 to become perfect cube...
___________________________________________
HOPE THIS HELPS YOU.....
Here's your answer....
The given number is 1719
we have to do prime factorization....
1719 - 3*3*191
1719 - 3^2 * 191
The power of 3 is 2
the power of 191 is one
To become a perfect cube...the power should be 3
so....we have to multiply 191 two times...and 3 should be multiplied one time...
191*191*3
109443
109443 should be multiplied with 1719 to become perfect cube...
___________________________________________
HOPE THIS HELPS YOU.....
sheetalkapoor95:
Thanks dear but sorry to say that plz. go through the question one more time. If it would be square then I will also find the answer but question is about perfect cube.. Plz. read it again.
That's OK... No probs... But thanx for your effort ☺
Thanku so much ☺
Yeah! I have seen it and match it with my answer... I only just wanted to verified it... Now I get to know that my answer was correct... Actually answer was too lengthy that's why I was little bit confused....
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