what length of a solid cylinder 2 cm in diameter must be taken to recast into a hollow cylinder of length 16 cm, external diameter 20 cm and thickness 2.5 millimetre
Answers
||✪✪ QUESTION ✪✪||
what length of a solid cylinder 2 cm in diameter must be taken to recast into a hollow cylinder of length 16 cm, external diameter 20 cm and thickness 2.5 millimetre ?
|| ★★ FORMULA USED ★★ ||
- Volume of Solid Cylinder = π * r² * h
- Volume of Hollow Cylinder = π * (R² - r²) * H
- Internal Radius of Hollow Cylinder = ( External Radius - Thickness) .
- when A solid is recast to form New Solid , than their Volume will be same .
- 1cm = 10mm.
- Radius = (Diameter /2)
|| ✰✰ ANSWER ✰✰ ||
→ Diameter of Solid Cylinder = 2cm.
→ Radius of Solid Cylinder = (2/2) = 1cm.
→ Height of Solid Cylinder = Let h cm.
Than,
→ Volume of Solid cylinder = π * r² * h = π * (1)² * h = π*h cm³ ------------ Equation (1)
______________________
Now,
→ Height of Hollow Cylinder = 16cm.
→ External Diameter = 20cm.
→ External Radius = R = (20/2) = 10cm.
→ Internal Radius = r = (10 - (2.5/10) ] = (10 - 0.25) = 9.75cm.
So,
→ Volume of Hollow Cylinder = π * 16 * [ (10)² - (9.75)²] = 16π * [ 100 - 95.0625] = (16π * 4.9375) cm³ ---- Equation (2) .
_______________________
Now, Since Volume of Both Will be same, So, Comparing Both Equations Now, we get,
→ π * h = 16 * π * 4.9375
π will be Cancel From both Sides,
→ h = (16 * 4.9375)
→ h = 79cm.
•°• Length of Solid Cylinder was 79cm.
Answer :-
79 cm
Solution :-
External diameter of the hollow cylinder = 20 cm
External radius of the hollow cylinder ( R ) = 20/2 = 10 cm
Thickness of the hollow cylinder = 2.5 mm = 2.5/10 cm = 0.25 cm
[ Since 1 cm = 1/10 mm ]
Inner radius of the hollow cylinder ( r ) = 10 - 0.28 = 9.75 cm
Length of the hollow cylinder i.e height ( h ) = 16 cm
Diameter of the solid cylinder = 2 cm
Radius of the solid cylinder ( r' ) = 2/2 = 1 cm
Let the length of the solid cylinder i.e height be h' cm
Given
Solid cylinder is recasted into a hollow cylinder
Therefore, Volume of solid cylinder = Volume of hollow cylinder
⇒ π * ( r' )² * h' = π * (R² - r²) * h
Cancelling π on both sides
⇒ ( r' )² * h' = (R + r)(R - r) * h
⇒ 1² * h' = (10 + 9.75)(10 - 9.75) * 16
⇒ 1 * h' = 19.75 * 0.25 * 16
⇒ h' = 4.9375 * 16
⇒ h' = 79