Question

What length of a wire of specific resistance 2*10^-6 ohm and cross sectional area is 5mm^2 should be taken to form a coil of resistance 10 ohm

Answer 1

Answer:

25 m

Explanation:

p(rho)=2*10^-6

R=10 ohm

A=5*10^-6

R=p l/A

10=2*10^-6 l / 5* 10^-6

10 * 5* 10^-6 / 2* 10^-6= l

25 m = length