Question

What length of Canvas 3 m wide will be required to make a conical tent of height 8 m and radius of base 6 m.( use pie =3.14)

Answer 1

We have,
Height of the conical tent, h=8 m,
Radius of the conical tent, r=6 m and
Widht of the canvas, B=3 m
Let the length of the canvas required be L.Also, the slant height of the conical tent, l=h2+r2‾‾‾‾‾‾‾√=82+62‾‾‾‾‾‾‾√=64+36‾‾‾‾‾‾‾√=100‾‾‾‾√=10 cmNow,The curved surface area of the conical tent=πrl=3.14×6×10=188.4 cm2⇒Area of the canvas required=188.4 cm2⇒LB=188.4⇒L×3=188.4⇒L=188.43∴ L=62.8 cm

So, the length of the canvas required to make the conical tent is 62.8 cm.