what length of talpaulin 3m wide will be required to make conical tent of height 8m and Base radius 6m. assume that the extra length of material that will required for stitching margins and wastage in cutting is 20m
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Height (h) of conical tent = 8 m
Radius (r) of base of tent = 6 m
Slant height (l) of tent =√r^2+h^2
m=(√6^2+8^2)
m=(√100)
m=10m
CSA of conical tent = πrl
= (3.14 × 6 × 10) m^2
= 188.4 m^2
Let the length of tarpaulin sheet required be l.
As 20 cm will be wasted, therefore, the effective length will be (l − 0.2 m).
Breadth of tarpaulin = 3 m
Area of sheet = CSA of tent
[(l − 0.2 m) × 3] m = 188.4 m^2
l − 0.2 m = 62.8 m
l = 63 m
Therefore, the length of the required tarpaulin sheet will be 63 m.
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Radius (r) of base of tent = 6 m
Slant height (l) of tent =√r^2+h^2
m=(√6^2+8^2)
m=(√100)
m=10m
CSA of conical tent = πrl
= (3.14 × 6 × 10) m^2
= 188.4 m^2
Let the length of tarpaulin sheet required be l.
As 20 cm will be wasted, therefore, the effective length will be (l − 0.2 m).
Breadth of tarpaulin = 3 m
Area of sheet = CSA of tent
[(l − 0.2 m) × 3] m = 188.4 m^2
l − 0.2 m = 62.8 m
l = 63 m
Therefore, the length of the required tarpaulin sheet will be 63 m.
HOPE IT HELPS YOU IF HELPED PLZ FOLLOW ME AND PLZ MARK THIS ANSWER AS BRAINLIST......
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