Question

what length of tarpaulin 2 m wide will be required to make a conical tent of height 12 m and base radius 5 m ? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is 95 cm. (use it = 3.14)​

Answer 1

Answer:

Given a conical tent with

Height ( h ) = 8m

Radius ( r ) = 6m

So, its length = l2 = h2 + r2

= l2 = ( 8 )2m + ( 6 )m2

= l2 = 64m + 36m

= l2 = 100m

= l = 10m

Curved surface area of the cone = TTrl

= 3.14 x 6m x 10m

= 188.4 cm2

The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m

So, its length = l - 0.2m

and its width = 3m

area of sheet = CSA of tent

so the area of the trapaulln = l x b

= ( l - 0.2m ) x 3m = 188.4m2

= l - 0.2m = 62.8m2

= l = 63m

Therefore, length of the trapaulin sheet required is 63m.

Step-by-step explanation:

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