Question

What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m
and base radius 6 m? Assume that the extra length of material that will be required for
stitching margins and wastage in cutting is approximately 20 cm (Use
pi = 3.14).


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Answer 1

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Answer 2

$h = 8m \\ r = 6m \\ \\ ∴l = \sqrt{ {r}^{2} + {h}^{2} } \\ \\ = \sqrt{( {6})^{2} + ( {8})^{2} } = \sqrt{36 + 64} \\ \\ = \sqrt{100} = 10m \\ \\ ∴curved \: surface \: area = \pi r l \\ \\ = 3.14 \times 6 \times 10 = {188.4m}^{2} \\ \\width \: of \: trapaulin = 3m \\ \\ ∴length \: of \: trapaulin = \frac{188.4}{3} = 62.8m \\ \\ extra \: length \: of \: the \: material \: required \\ = 20cm = 0.2m \\ \\ ∴actual \: length \: of \: trapaulin \: required \\ = 62.8m + 0.2m = 63m$