What length of tarpaulin 3 m wide will be required to make a conical tent of height 8m and Base radius 6m? Assume that extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use pie 3.14)
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Answer:
h = Height of tent = 8 m
r = Base radius = 6 m
Therefore,
l=
r
2
+h
2
=10 m
Curved surface area of the cone = πrl=3.14×6×10 m
2
Therefore, length of 3 m wide tarpaulin required =
3
3.14×6×10
=62.8 m
Extra length required = 0.2 m
Therefore, total length required = 63 m
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